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A mixture of 2 moles of helium gas ((ato...

A mixture of 2 moles of helium gas (`(atomic mass)=4a.m.u`) and 1 mole of argon gas (`(atomic mass)=40a.m.u`) is kept at 300K in a container. The ratio of the rms speeds `((v_(rms)(helium))/((v_(rms)(argon))` is

A

0.32

B

2.24

C

3.16

D

1

Text Solution

Verified by Experts

The correct Answer is:
C
`"Vrms"=sqrt((3 RT)/M)`
`"Vrms(He)"/"Vrms(Ar)"=sqrt(M/M"argon")`
`"Vrms(He)"/"Vrms(Ar)"=sqrt(40/4)=sqrt10=3.16`
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