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A thermodynamical system undergoes cycli...

A thermodynamical system undergoes cyclic process ABCDA as shown in figure work done by the system is

A

Zero

B

`2P_0V_0`

C

`P_0V_0`

D

`3/2 P_0V_0`

Text Solution

Verified by Experts

The correct Answer is:
A
As it is clear from figure,

`W_(BCOB)=-"area of" DeltaBCO=-(P_0V_0)/2`
`W_"AODA"=+"area of" DeltaAOD=+P_0V_0`
`:. W_"net"=W_"BCOC"+W_"AODA"=-(P_0V_0)/2+(P_0V_0)/2="zero"`
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