A rod `AB` of length `2m` is hinging at point A and its other end B is attached to a platform on which a point of mass m is kept. Rod rotates about point `A` maintain angle `theta = 30^(@)` with the vertical in such a way that platform remain horizontal and revolves on the horizontal circular path. If the coefficient of static friction between the block and platform is `mu = 0.1` then find the maximum angular velocity in rad`s^(-1)` of rod so that the block does not slip on the platform `(g = 10 ms^(-2))`

Answer

`01.00`

Explanation

`N=mg, muN=meomega^2`
`mumh=m2sinthetaomega^2`
`implies" "omega=sqrt((mutheta)/(2 sin theta))=sqrt((0.1 xx 10)/(2 xx sin 20))`
`=1 rads^-1`