A galvanometer coil has a resistance `90 Omega` and full scale deflection current `10 mA`. A `910 Omega` resistance is connected in series with the galvanometer to make a voltmeter. If the least count of the voltmeter is `0.1 V` the number of divisions on its scale is

Answer

100

Explanation

`V_("max") = (I_("max")) R_(g) + R_(s))`
`= (10 xx 10^(-3)) (1000)`
= 10 V
L.C. = 0.1 V
N(L.C.) = `V_("max")`
`rArr N = 10/0.1 = 100`