Show that: `DeltaAEP~DeltaADB`

In the figure , altitudes AD and CE of DeltaABC intersect each other at the point P . Show that : DeltaAEP~DeltaCDP

In the figure given below altiudes AD and CE of DeltaABC intersect each other at the point P. Show that . DeltaAEP~DeltaCDP

In the adjoining figure, DeltaABC is an isosceles triangle in which AB = AC and AD is the bisector of angleA . Prove that: DeltaADB~=DeltaADC

In the adjoining figure, DeltaABC is an isosceles triangle in which AB = AC and AD is a median. Prove that: DeltaADB~=DeltaADC

In the adjoining figure, AD = DC and bisects angleADC . Prove that DeltaADB cong DeltaCDB .

Given AD=DC and DB biscets angleADC . (i) Prove that, DeltaADB cong DeltaCDB (ii) If angleABD=48^(@) , find angleCBD .

Assertion : In a quadrilateral ACBD, AC = AD and AB bisects angleA (see figure) then DeltaACB ~= DeltaADB by SAS congruence criteria. Reason : Two triangles are congruent if two sides and the included angle of one triangle is equal to the corresponding two sides and included angle of the other.

In the given figure, D and E are the points on the base BC of DeltaABC such that BD=CE, AD= AE and angleADE=angleAED , prove that DeltaADB cong DeltaAEC .

In the following figure O is the centre of the circel. If angleACB=60^(@) and DA=DB then prove that DeltaADB is an equilateral triangle.

Show that is irrational.