In the given figure, AB is the diameter of the largest semi-circle. AB = 21 cm, AM = MN = NB. Semi-circles are drawn with AM, MN and NB as shown. Using `pi = (22)/(7)`, calculate the area of the shaded region.

In the given figure,diameter of larger semi- circle is 14cm and radius of smaller semi- circle is 3.5cm. find :

In the figure given below, ABCD is the diameter of a circle of radius 9 cm. The lengths AB, BC and CD are equal. Semicircles are drawn on AB and BD as diameters as shown in the figure. What is the area of the shaded region ?

In the given figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. Find the area of the shaded region.

In the given figure,ABCD is a square of side 14cm. Semi-circles are drawn with each side of square as diameter.Find the area of the shaded region.Use pi=(22)/(7)

PQRS is the diameter of a circle of radius 6 cm. The lengths PQ, QR and RS are equal. Semi-circles are drawn with PQ and QS as diameters as shown in the figure alongside. Find the ratio of the area of the shaded region to that of the unshaded region.

In the figure, ABCD is a square of side 14 cm. Semi-circles are drawn with each side of square as diameter. Find the area of the shaded region.

PQRS is a diameter of a circle of radius 6cm. The lengths PQ,QR and RS are equal.Semi- circles are drawn on PQ and QS as diameters as shown in figure.Find the perimeter of the shaded region.

In figure, find the area of the shaded region. ("Use" pi = (22)/(7))