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If the sum of the circumferences of two ...

If the sum of the circumferences of two circles with radii `R_1 and R_2` is equal to the circumference of a circle of radius R, then

A

`R_1 + R_2 = R`

B

`R_1 + R_2 gt R`

C

`R_1 + R_2 lt R`

D

`R_1^2 + R_2^2lt R`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to use the formula for the circumference of a circle, which is given by: \[ C = 2\pi R \] where \( R \) is the radius of the circle. ### Step-by-Step Solution: 1. **Calculate the Circumference of the Two Circles:** - The circumference of the first circle with radius \( R_1 \) is: \[ C_1 = 2\pi R_1 \] - The circumference of the second circle with radius \( R_2 \) is: \[ C_2 = 2\pi R_2 \] 2. **Sum the Circumferences:** - The total circumference of the two circles is: \[ C_{total} = C_1 + C_2 = 2\pi R_1 + 2\pi R_2 = 2\pi (R_1 + R_2) \] 3. **Circumference of the Circle with Radius \( R \):** - The circumference of the circle with radius \( R \) is: \[ C = 2\pi R \] 4. **Set the Two Circumferences Equal:** - According to the problem, the sum of the circumferences of the two circles is equal to the circumference of the circle with radius \( R \): \[ 2\pi (R_1 + R_2) = 2\pi R \] 5. **Simplify the Equation:** - We can divide both sides by \( 2\pi \) (assuming \( \pi \neq 0 \)): \[ R_1 + R_2 = R \] ### Conclusion: From the above steps, we conclude that the sum of the radii \( R_1 + R_2 \) is equal to the radius \( R \).
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