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Which of the following are not ionic com...

Which of the following are not ionic compound/
(i) KCI
(ii) HCI
(iii) `CCI_(4)`
(iv) NaCI

A

(i) and (ii)

B

(ii) and (iii)

C

(iii) and (iv)

D

(i) and (iii)

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given compounds are not ionic compounds, we need to analyze each compound based on the type of bonding present in them. ### Step-by-Step Solution: 1. **Identify the Compounds**: We have four compounds to analyze: - (i) KCl - (ii) HCl - (iii) CCl₄ - (iv) NaCl 2. **Analyze KCl**: - KCl (Potassium Chloride) is formed from potassium (K) and chlorine (Cl). - Potassium donates one electron to chlorine, resulting in the formation of K⁺ and Cl⁻ ions. - Since there is a transfer of electrons, KCl is an **ionic compound**. 3. **Analyze HCl**: - HCl (Hydrochloric Acid) consists of hydrogen (H) and chlorine (Cl). - In HCl, hydrogen and chlorine share electrons to form a covalent bond. - There is no transfer of electrons, so HCl is a **covalent compound**. 4. **Analyze CCl₄**: - CCl₄ (Carbon Tetrachloride) is made up of carbon (C) and chlorine (Cl). - In CCl₄, carbon shares its four valence electrons with four chlorine atoms, forming covalent bonds. - Since there is sharing of electrons, CCl₄ is also a **covalent compound**. 5. **Analyze NaCl**: - NaCl (Sodium Chloride) is formed from sodium (Na) and chlorine (Cl). - Sodium donates one electron to chlorine, resulting in the formation of Na⁺ and Cl⁻ ions. - As there is a transfer of electrons, NaCl is an **ionic compound**. 6. **Conclusion**: - From the analysis, we find that: - KCl is ionic. - HCl is covalent. - CCl₄ is covalent. - NaCl is ionic. - Therefore, the compounds that are **not ionic** are HCl and CCl₄. ### Final Answer: The compounds that are not ionic compounds are **(ii) HCl and (iii) CCl₄**. Thus, the correct option is **B (2 and 3)**.

To determine which of the given compounds are not ionic compounds, we need to analyze each compound based on the type of bonding present in them. ### Step-by-Step Solution: 1. **Identify the Compounds**: We have four compounds to analyze: - (i) KCl - (ii) HCl - (iii) CCl₄ ...
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