An electric lamp of `100 Omega`, a toaster of resistance `50 Omega` and a water filter of resistance `500 Omega` are connected in parallel to a `220 V` source. What is the resistance of an electric iron connected to the same source that takes as much current as all three appliances and what is the current through it ?

Explanation

Given that the electric lamp of 100 `omega`, a toaster of resistance 50 `omega` and water filter of resistance 500 `omega` are connected in parallel. The net resistance in parallel is given by Now, using Ohm.s Law V = IR, We have `I=(V )/(R )=(220V )/(31.25 omega)=7.40 A`
The resistance of the electric iron would be 220`//`7.04 = 31.25 ohm which is connected to the same source drawing 7.04 A current.