How can three resistors of resistances `2 Omega,3 Omega`, and `6 Omega` be connected to give a total resistance of
(a) `4 Omega`
(b) `1 Omega` ?

Explanation

To get total resistance 1 `omega`, connect 2 `omega, 3 omega` and 6 `omega` resistors in parallel. The net resistance in parallel is given by Here, `R_(1)=2 omega,R_(2) = 3omega` and `R_(3) = 6 omega` So
`(1)/(R )=1/2+1/3+1/6`
`=(3+2+1)/(6)=6/6 omega`
`rarr R=6/6 =1 omega`