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An electric iron of resistance 20 Omega ...

An electric iron of resistance `20 Omega` takes a current of `5 A`. Calculate the heat developed in `30 s`.

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According to Joule.s law of heating, the amount of heat produced is given by H = VI t Where, V= I R = 5 A x 20 `omega` = 100 V I = 5A t = 30 Seconds So, H = 100 x 5 x 30 J = 15000 J = 1.5 x `10^(4)` J
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