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A battery of 9 V is connected in series ...

A battery of `9 V` is connected in series with resistors of `0.2 Omega, 0.3 Omega, 0.4 Omega, 0.5 Omega and 12 Omega`. How much current would flow through the `12 Omega` resistor ?

Text Solution

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Total resistance of resistors when connected in series is given by: According to ohm .s law V=IR
There is no current division occurring in a series circuit. So, the current through the 12 ohm resistor will be same as 0.67 A.
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