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How many 176 Omega resistors (in parall...

How many `176 Omega` resistors (in parallel) are required to carry 5 A in 220 V line ?

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Let the total number of resistors be x. Given that, Current I = 5A and the potential difference V = 220 V According to Ohm.s law, V = IR
`rarrR=(V)/(I)=220/5=44 omega`
Now for x number of resistors of resistance 176 `omega` the equivalent resistance of the resistors connected in parallel is 44 `omega`
`1/44=1/176+1/176+1/176+1/176+...` to x times
`rarr x=176/44=4`
Therefore, 4 resistors of 176 `omega` are required to draw the given amount of current.
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