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A current of 1 A is drawn by a filament ...

A current of `1 A` is drawn by a filament of an electric bulb. Number of electrons passing through a cross-section of the filament in `16` seconds would be roughly :

A

`10^(20)`

B

`10^(16)`

C

`10^(18)`

D

`10^(23)`

Text Solution

Verified by Experts

The correct Answer is:
A
Given `I=1 Amp`
`t=16 sec `
`N=(IxxT)//e=(1xx16)//(1.6xx10^(-19))`
`N=10^(20)`
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