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Show how would you join three resistor...

Show how would you join three resistors, each of resistance `9 Omega` so that the equivalent resistance of the combination is (i) `13.5 Omega` , (ii) `6 Omega` ?

Text Solution

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Two 9 ohm resistors in parallel connected to one 9 ohm in series
`(1)/(R_(p))=1/9+1/9=2/9`
`R=9 omega+9/2omega=13.5 omega`
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