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Show how would you join three resistor...

Show how would you join three resistors, each of resistance `9 Omega` so that the equivalent resistance of the combination is (i) `13.5 Omega` , (ii) `6 Omega` ?

Text Solution

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Two 9 ohm resistors in series connected to one 9 ohms in parallel
`R_(s)=9 omega+9 omega=18 omega`
`(1)/(R )=(1)/(18)+1/9=3/18`
`therefore R=6 omega`
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