An electric lamp, whose resistance is `20 Omega` and a conductor of `4 Omega` resistance are connected to a `6 V` battery as shown in (Fig. 3.18) Calculate.
(a) the total resistance of the circuit,
(b) the current through the circuit, and
( c) the potential difference across the electric lamp and the conductor.
.

Explanation

`R=R_(1)+R_(2)`
`=20 omega+4 omega=24 omega`
Given voltage battery V=6V
Resistance of electric lamp `R_(1)=20 omega`
Resistance of series conductor `R_(2)=4 omega`
Total resistance of circuit `R_("total" )=R_(1)+R_(2)`
`=520 omega+4 omega`
`=24 omega`