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Consider the given circuit and find the ...

Consider the given circuit and find the current flowing in the circuit and potential difference across the 15 `omega` resistor when the circuit is closed.

Text Solution

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Total resistance of the circuit = `R = R_(1) + R_(2) + R_(3) = 5 + 10 +15 = 30` ohm 1 Potential difference across the circuit `//` By ohm.s law
V=IR or `I=(V )/(r )=(30 V)/(30 "ohm")=1A`
Potential difference across 15 ohm Resistor
=1 A `xx` 15 ohm =15 volt
`R_("eq")=R_(1)+R_(2)+R_(3)`
`=5 omega+10 omega+15 omega=30 omega`
electric current (I)=`(V )/(R_("eq"))`
`30/30 =1A`
Potential difference across 15 `omega` resistor =IR
`=1xx15=15V`
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