Let `veca, vecb, vec c` form sides `BC, CA ` and `AB` respectively of a triangle ABC then

If the vectors veca,vecb,vecc form the sides BC,CA and AB respectively of a triangle ABC then (A) veca.(vecbxxvecc)=vec0 (B) vecaxx(vecbxvecc)=vec0 (C) veca.vecb=vecc=vecc=veca.a!=0 (D) vecaxxvecb+vecbxxvecc+veccxxvecavec0

If the vectors veca,vecb,vecc form the sides BC,CA and AB respectively of a triangle ABC then (A) veca.(vecbxxvecc)=vec0 (B) vecaxx(vecbxvecc)=vec0 (C) veca.vecb=vecc=vecc=veca.a!=0 (D) vecaxxvecb+vecbxxvecc+veccxxvecavec0

If the vectors veca,vecb,vecc form the sides BC,CA and AB respectively of a triangle ABC then (A) veca.(vecbxxvecc)=vec0 (B) vecaxx(vecbxvecc)=vec0 (C) veca.vecb=vecc=vecc=veca.a!=0 (D) vecaxxvecb+vecbxxvecc+veccxxvecavec0

If the veactors veca, vecb and vecc form the sides BC,CA and AB respectively of triangle ABC, then :

It the vectors vec(a), vec(b) and vec(c) form the sides vec(BC), vec(CA) and vec(AB) respectively of a triangle ABC, then write the value of vec(a) xx vec(c) + vec(b) xx vec(c) .

If the vectors vec(a), vec(b), vec(c ) form the sides vec(BC), vec(CA), vec(AB) respectively of triangle ABC then show that vec(a) xx vec(b) = vec(b)xx vec(c ) = vec(c ) xx vec(a) .

Let D, E and F be the middle points of the sides BC,CA and AB, respectively of a triangle ABC. Then prove that vec AD+vec BE+vec CF=vec 0