A. vessel contains 5 litres of Liquid A and 20 litres of Liquid B. 20% of the contents of the vessel are removed. To the remaining contents, x litres of Liquid A is added to reverse the ratio of Liquid A and Liquid B. Then y litres of Liquid B is added again to reverse the ratio of Liquid A and Liquid B. Quantity I: Value of 'y' Quantity II: Value of 'x' (a) Quantity I = Quantity II or No relation (b) Quantity I ≤ Quantity II (c) Quantity I ≥ Quantity II (d) Quantity I > Quantity II
Find the appropriate relation for quantity 1 and quantity 2 in the following question : Quantity I : the unit digit in (6817)^(754) Quantity II : the unit digit in (3^(65)xx6^(59)xx7^(71))
Assertion (A): A physical quantity which can be described with both magnitude and direction is called as a vector quantity. Reason (R): All vector quantities are derived quantities.
Physical Quantity|Types Of Physical Quantity|Units|Types Of Units|OMR
Quantity I: Area of square, given in figure, in 40% of the area of rectangle. Valuw of percent y which length of rectangle is more than breadth. Quantity II: A pair of opposite sides of a square when increased by 15 cm, the area of figure increased by 600 cm^(2). Value of percent by which area increased. (a) Quantity I > Quantity II (b) Quantity I = Quantity II (d) Quantity I <= Quantity II
In the following question two Quantities i.e., Quantity I and Quantity II are given. You have to determine the relation between Quantity I and Quantity II. ‘a’, ‘b’ and ‘c’ are positive integers. Quantity I: Value of a in ((a+b)^2 - (a-b)^2)/(8ab(a+b)^2) =1 Quantity II: Value of c in ((c+b)^3-(c-b)^3)/(b^2+3c^2)^2= 1/(8b)
A scalar quantity
Physical Quantity |Fundamental Quantity|Derived Quantity|Supplementary Quantity|Magnitude|Unit|SI Prefix |Dimensions|Dimension Formula
The Physical Quantities|Fundamental Quantities|Derived Quantities|Supplimentary Quantities|Unit|Important Points|Summary
