Home
Class 11
CHEMISTRY
What is the wavelength of the radiation ...

What is the wavelength of the radiation emitted producing a line in a Lyman series when an electron falls from fourth stationary state in hydrogen atom ? `R_H = 1.1 xx 10^7 m^(-1)`

A

96.97 nm

B

969.7nm

C

9.697nm

D

None

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

The ionization energy of hydrogen atom in the ground state is 1312 kJ "mol"^(-1) . Calculate the wavelength of radiation emitted when the electron in hydrogen atom makes a transition from n = 2 state to n = 1 state (Planck’s constant, h = 6.626 xx 10^(-34) Js , velocity of light, c = 3 xx 10^8 m s^(-1) , Avogadro’s constant, N_A = 6.0237 xx 10^23 "mol"^(-1) ).

Calculate the wave number of the spectral line when electron jumps from the seond Bohr orbit to the ground state. R = 1.097xx 10^(7) m^(-1)

Calculate the shortest and longest wavelength of Balmer series of hydrogen atom. Given R=1.097 xx 10^(7)m^(-1) .

The wave number of the series limiting line for the Lyman series for hydrogen atom is (R =109678cm^(-1) )

The radius of the first orbit of electron in hydrogen atom (e=1.6xx10^(-19)" coulomb,

Calculate the wavelength and wave numbers of the first and second lines in tbe Balmer series of hydrogen spectrum. Given R = 1.096xx10^(7) m^(-1)