There is a group of six persons living in a four-storeyed building. The persons are A, B, C, E and F. Each storey of the building has two flats, thus there are eight flats in all, two of them being empty.
(ii) The heaviest of the group lives on top floor while the lightest lives on the ground floor.
(iii) C is heavier than B, who, in turn, is heavier than F.
(iv) E is lighter than D.
(v) One of the flats on the first floor is vacent while one on the second floor is also vacant.
(vi) A is neither the heaviest nor the lightest.
(vii) There are only two people heavier than C, A is not one of them.
(viii) B shares the floor with the heaviest of the group while C shares it with the highest.
Who among the following is the heaviest of the group ?

Options

A. D
B. C
C. A
D. Can't be say

Answer

A

Explanation

We have from (iii) and (iv)
`CgtBgtF`
and `DgtE` [in increasing order of weights]
Now, A is neither the heaviest nor the lighter. Also, C is lighter than only two people and A is not one of them.
But B and F are already lighter than C. And A is not heaviest than C.
Hence, the remaining two , viz. D and e, must be heavier than C. Thus, we may conbine the two series as :
`DgtEgtCgtBgtF`.
In the above , A must come after C but before F [after C because C is lighter than only two, before F because A is not the lightest.]
Hence, there are two possibilities:
`DgtEgtCgtAgtBgtF`
or
`DgtEgtCgtBgtAgtF`
Now, the heaviest is on the top floor along with B and the lightest is on the ground floor along with C. Thus, D (the heaviest ) and b are on the top floor while F (the lightest) and C are on the ground floor. Since the two middle floors have one flat vacant each, E and a occupy the middle two floors, one each of one floor. The two possible ways are :