`tan^(-1) ((cosx - sinx)/(cosx + sinx))`, 0<`x`<`pi`

Find the derivative of tan^(-1)((cosx - sinx)/(cosx + sinx)) with respect to 'x'

Differentiate tan^(-1)((a cosx-b sinx)/(b cosx + a sinx)) w.r.t. x.

cot^(-1)((cosx-sinx)/(cosx+sinx))

tan^(-1)((cosx+sinx)/(cos x-sinx))

Express each of the following in the simplest form: tan^(-1){(cosx)/(1-sinx)},\ -pi/2

Differentiate each of the following w.r.t. x: (i) tan^(-1)((1-cosx)/(sinx))" "(ii)tan^(-1)((cos x -sinx)/(cosx +sinx))

Prove that: tan^(-1){(a cosx-b sinx)/(b cosx+a sinx)} =tan^(-1)((a)/(b))-x

Find- tan^-1((cosx+sinx)/(cosx-sinx))

cosx-sinx=-1