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(0.39xx0.39+0.17xx0.17)/((0.39+0.17)^(2)...

`(0.39xx0.39+0.17xx0.17)/((0.39+0.17)^(2)+(0.39-0.17)^(2))` equal to :

A

1

B

0

C

`1//2`

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \((0.39 \times 0.39 + 0.17 \times 0.17) / ((0.39 + 0.17)^{2} + (0.39 - 0.17)^{2})\), we can simplify it step by step. ### Step-by-Step Solution: 1. **Substitute Variables**: Let \( A = 0.39 \) and \( B = 0.17 \). The expression now becomes: \[ \frac{A \times A + B \times B}{(A + B)^{2} + (A - B)^{2}} \] 2. **Rewrite the Numerator**: The numerator can be simplified as: \[ A^2 + B^2 \] 3. **Expand the Denominator**: The denominator consists of two parts: - \( (A + B)^{2} = A^2 + 2AB + B^2 \) - \( (A - B)^{2} = A^2 - 2AB + B^2 \) Adding these two expansions together gives: \[ (A + B)^{2} + (A - B)^{2} = (A^2 + 2AB + B^2) + (A^2 - 2AB + B^2) = 2A^2 + 2B^2 \] 4. **Combine the Results**: Now, we can substitute back into the expression: \[ \frac{A^2 + B^2}{2A^2 + 2B^2} \] 5. **Factor Out Common Terms**: The denominator can be factored as: \[ 2(A^2 + B^2) \] Thus, the expression simplifies to: \[ \frac{A^2 + B^2}{2(A^2 + B^2)} \] 6. **Cancel Common Terms**: Since \( A^2 + B^2 \) is common in both the numerator and the denominator (assuming \( A^2 + B^2 \neq 0 \)), we can cancel it out: \[ \frac{1}{2} \] ### Final Answer: The value of the expression is: \[ \frac{1}{2} \]
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