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A can complete a piece of work in 36 day...

A can complete a piece of work in 36 days, B in 54 days and C in 72 days. All the three began the work the work together but A left 8 days before the completion of the work and B 12 days before the completion of work. Only C worked up to the end. In how many days was the work completed?

A

24

B

25

C

27

D

30

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will first determine the work done by A, B, and C in one day and then calculate the total work completed when they work together, considering the days they leave early. ### Step 1: Determine the work done by A, B, and C in one day. - A can complete the work in 36 days, so the work done by A in one day is: \[ \text{Work done by A in one day} = \frac{1}{36} \] - B can complete the work in 54 days, so the work done by B in one day is: \[ \text{Work done by B in one day} = \frac{1}{54} \] - C can complete the work in 72 days, so the work done by C in one day is: \[ \text{Work done by C in one day} = \frac{1}{72} \] ### Step 2: Find the total work done by A, B, and C together in one day. To find the total work done by A, B, and C in one day, we add their individual work rates: \[ \text{Total work done in one day} = \frac{1}{36} + \frac{1}{54} + \frac{1}{72} \] To add these fractions, we need to find a common denominator. The least common multiple (LCM) of 36, 54, and 72 is 216. Now, we convert each fraction: - \(\frac{1}{36} = \frac{6}{216}\) - \(\frac{1}{54} = \frac{4}{216}\) - \(\frac{1}{72} = \frac{3}{216}\) Thus, \[ \text{Total work done in one day} = \frac{6 + 4 + 3}{216} = \frac{13}{216} \] ### Step 3: Set up the equation based on the work done. Let \(X\) be the total number of days taken to complete the work. - A works for \(X - 8\) days (leaves 8 days before completion). - B works for \(X - 12\) days (leaves 12 days before completion). - C works for \(X\) days. The work done by each person can be expressed as: - Work done by A: \(\frac{6}{216} \times (X - 8)\) - Work done by B: \(\frac{4}{216} \times (X - 12)\) - Work done by C: \(\frac{3}{216} \times X\) ### Step 4: Write the total work equation. The total work done by A, B, and C together must equal 1 (the whole work): \[ \frac{6}{216}(X - 8) + \frac{4}{216}(X - 12) + \frac{3}{216}X = 1 \] ### Step 5: Simplify the equation. Multiplying through by 216 to eliminate the denominator: \[ 6(X - 8) + 4(X - 12) + 3X = 216 \] Expanding the equation: \[ 6X - 48 + 4X - 48 + 3X = 216 \] Combining like terms: \[ (6X + 4X + 3X) - 96 = 216 \] \[ 13X - 96 = 216 \] ### Step 6: Solve for \(X\). Adding 96 to both sides: \[ 13X = 216 + 96 \] \[ 13X = 312 \] Dividing by 13: \[ X = \frac{312}{13} = 24 \] ### Conclusion The total number of days taken to complete the work is **24 days**.
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