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A can complete a project in 20 days and ...

A can complete a project in 20 days and B can complete the same project in 30 days. If A and B start working on the project together and A quits 10 days before the project is completed, in how many days will the project be completed?

A

18

B

27

C

26.67

D

16

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to determine how many days it will take for A and B to complete the project together, given that A quits 10 days before the project is finished. ### Step 1: Determine the work rates of A and B - A can complete the project in 20 days. Therefore, A's work rate is: \[ \text{Work rate of A} = \frac{1}{20} \text{ of the project per day} \] - B can complete the project in 30 days. Therefore, B's work rate is: \[ \text{Work rate of B} = \frac{1}{30} \text{ of the project per day} \] ### Step 2: Combine their work rates When A and B work together, their combined work rate is: \[ \text{Combined work rate} = \frac{1}{20} + \frac{1}{30} \] To add these fractions, we need a common denominator, which is 60: \[ \frac{1}{20} = \frac{3}{60}, \quad \frac{1}{30} = \frac{2}{60} \] Thus, \[ \text{Combined work rate} = \frac{3}{60} + \frac{2}{60} = \frac{5}{60} = \frac{1}{12} \] This means together, A and B can complete \(\frac{1}{12}\) of the project in one day. ### Step 3: Set up the equation for total work Let \(x\) be the total number of days the project takes to complete. Since A quits 10 days before the project is completed, A works for \(x - 10\) days, and B works for all \(x\) days. The work done by A in \(x - 10\) days is: \[ \text{Work done by A} = \frac{1}{20} \times (x - 10) \] The work done by B in \(x\) days is: \[ \text{Work done by B} = \frac{1}{30} \times x \] ### Step 4: Write the equation for total work The total work done by A and B together must equal 1 (the whole project): \[ \frac{1}{20}(x - 10) + \frac{1}{30}x = 1 \] ### Step 5: Solve the equation To solve the equation, we first find a common denominator for the fractions, which is 60: \[ \frac{3}{60}(x - 10) + \frac{2}{60}x = 1 \] Multiplying through by 60 to eliminate the fractions: \[ 3(x - 10) + 2x = 60 \] Expanding the equation: \[ 3x - 30 + 2x = 60 \] Combining like terms: \[ 5x - 30 = 60 \] Adding 30 to both sides: \[ 5x = 90 \] Dividing by 5: \[ x = 18 \] ### Final Answer The project will be completed in **18 days**. ---
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