If f(x)=cos(logx), then f(x^2)f(y^2)-(1)...

If `f(x)=cos(logx)`, then
`f(x^2)f(y^2)-(1)/(2)[f((x^2)/(y^2))+f(x^(2)y^(2))]` has the value :

A

`-2`

B

0

C

`1/2`

D

1

Verified by Experts

The correct Answer is:

D

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