If the base of an isosceles triangle is of length '2a' and the length of the altitude droped to the base is h (where `a gt 0 , h gt 0`) , then the distance of each side from the midpoint of the base of the triangle is

Options

A. `(ah)/sqrt(a^2+h^2)`
B. `(ah)/sqrt(a^2-h^2)`
C. `(ah)/sqrt(h^2-a^2)`
D. `sqrt(a^2+h^2)`

Answer

A