Home
Class 11
MATHS
The equation of the pair of lines throug...

The equation of the pair of lines through (1,-1) and perpendicular to the pair of lines `x^(2)-x y-2 y^(2)=0` is

A

`2x^2-xy+y^2+5x+y+2=0`

B

`x^2-xy-2y^2-5x-y-2=0`

C

`2x^2-xy-y^2+5x+y-2=0`

D

`2x^2-xy-y^2+5x+y-2=0`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

Equation of pair of lines drawn through (1, 1) and perpendicular to the pair of lines 3 x^(2)-7 x y+2 y^(2)=0 is

The equation to the pair of lines passing through (1,-1) and parallel to the pair of lines x^(2)-7 x y+12 y^(2)=0 is

Equation of pair of lines passing through (2,1) and perpendicular to the lines 6 x^(2)+17 x y+12 y^(2)=0 is

The equation of the pair of lines passing through the origin and perpendicular to the pair 10 x^(2)+4 x y-2 y^(2)=0 is

The equation of the line passing through (1, 2) and perpendicular to x+y+7=0 is :

The equation to the pair of lines through the origin and perpendicular to 5 x^(2)-y^(2)=0 is

The equation of the line passing through the point (3,2) and perpendicular to the line y=x is

Equation of the line passing through (1, 1,1) and perpendicular to 2x + 3y + z = 5 is:

The equation of the pair of bisectors of the angles between the pair of lines x^(2)-2 a x y-y^(2)=0 is x^(2)-2 b x y-y^(2)=0 . Then

The equation of the pair of lines passing through (0,1) and parallel to 2 x^(2)+5 x y+3 y^(2)+6 x+7 y+4=0 is