In quadrilateral ABCD, AB = CD, BC=AD show that `DeltaABC ~= DeltaCDA` Consider `DeltaABC and DeltaCDA`

In the given figure, AB||DC and AD||BC show that DeltaABC ~= Delta CDA .

In quadrilateral ABCD, AB = BC = CD = AD and AC ne BD then it is a .....

In quadrilateral ACBD, AC = AD and AB bisects /_A Show that DeltaABC~= DeltaABD . What can you say about BC and BD?

In the given figure angle ADE=angleB Show that DeltaABC~DeltaADE .

DeltaABC~DeltaPQR , AB:PQ=3:4 then ar DeltaABC : ar DeltaPQR =……

Prove that in a kite ABCD, DeltaABC and DeltaADC are congruent.

In a quadrilateral ABCD, angleB = 90^0 , AD^2 = AB^2 + BC^2 + CD^2 . Prove that angle ACD = 90 ^0 .

CD and GH are respectively the bisectors of angle ACB and angle EGF such that D and H lie on sides AB and FE of DeltaABC and Delta FEG respectively. IF DeltaABC~DeltaFEG then show that (CD)/(GH)=(AC)/(FG)

CD and GH are respectively the bisectors of angle ACB and angle EGF such that D and H lie on sides AB and FE of DeltaABC and Delta FEG respectively. IF DeltaABC~DeltaFEG then show that DeltaDCB~DeltaHGE