AB is a line - segment. P and Q are points on either side of AB such that each of them is equidistant from the points A and B (See Fig ). Show that the line PQ is the perpendicular bisector of AB.

AB is a line segment and line l is its perpendicular bisector. If a point P lies on l, show that P is equidistant from A and B.

A line segment AB is denoted as

The line 4x+3y+1=0 cuts the axes at A and B. The equation to the perpendicular bisector of AB is

P is a point equidistant from two lines l and m intersecting at point A (see figure). Show that the line AP bisects the angle between them.

P and Q are points on the line joining A(-2, 5), B(3, -1) such that AP = PQ = QB. Then the mid point of PQ is

If C is the midpoint of AB and P is any point outside AB, then

If P is (3, 1) and Q is a point on the curve y^2 = 8x , then the locus of the mid-point of the line segment PQ is

D is a point on side BC ΔABC such that AD = AC (see figure). Show that AB > AD.

If C is the mid point of AB and P is any point outside AB, then

A is a point on either of two line y+sqrt3absx=2 " at a distance of " 4/sqrt3 units from their point of intersection. The coordinates of the foot of perpendicular from A on the bisector of the angle between them are