`triangleABC` and `triangleDBC` are two isosceles triangles on the same base BC (see figure). Show that `angelABD = angelACD`.

DeltaABC and DeltaDBC are two isosceles triangles on thesame base BC (see figure). Show that /_ ABD = /_ ACD.

In the figure given below triangleABC and triangleDBC are two triangles such that AB=BD, and AC=CD. Show that triangleABC~=DBC

In te figure triangle PQR and triangle SQR are two triangles on the same base QR. If PS intersects QR at 'O' then triangle PQR : triangle SQR =

Let ABC be an isosceles triangle with BC as its base. Then, rr_(1)=

Observe the given figure and show that triangle EBL~= triangel ECD .

In angleABC , D is a point on side BC, triangleABC such that AD. AC (see figure).

In the adjacent figure, triangle ABC and triangle DBC are on the same base BC. If AD and BC intersect at O, Prove that (area of triangle ABC )/(area of triangle DBC) = (AO) /(DO)

D is a point on side BC ΔABC such that AD = AC (see figure). Show that AB > AD.

In the figure, ΔABC and ΔABD are two triangles on the same base AB. If line segment CD is bisected by bar(AB) at O, show that ar (DeltaABC) = ar (DeltaABD).