An organic compound on analysis gave the following percentage composition of C= 57.8, H= 3.6 and the rest is oxygen. Vapour density of the compound is 83. Find out the molecular formula of the compound.

A compound on analysis gave the following results C = 54.54% , H=9.09% and rest is oxygen and vapour density of the compound = 88. Determine the molecular formula of the compound.

An organic compound has the following percentage composition : C= 48%, H= 8% N= 28% and rest of oxygen. Calculate the empirical formula of the compound.

An organic substance containing carbon, hydrogen and oxygen gave following percentages, C= 40.68%, H_(2) = 5.085% and O_(2) = 54.22%. The vapour density of the compound is 59. Calculate the molecular formula of the compound.

An organic compound on analysis gave the following data : C = 57.82% , H = 3.6% and O = 38.58% . Find its empirical formula.

A substance on analysis gave the following percentage composition Na = 43.4% C = 11.3% O = 45.3% Calculate the empirical formula.

Write the empirical formula of the compounds having the molecular formulas : C6H6

Write the empirical formula of the compounds having the molecular formulas : B2H6

Write the empirical formula of the compounds having the molecular formulas : C6H12O6

Write the empirical formula of the compounds having the molecular formulas : C10H8

Determine the empirical formula of a compound with following percentage composition Cu= 47.3, Cl= 52.7.