A substance on analysis gave the following percentage composition Na = 43.4% C = 11.3% O = 45.3% Calculate the empirical formula.

An inorganic substance on analysis gave the following results Na = 29.1% S = 40.5% and O = 30.4% . Calculate its empirical formula.

An inorganic salt gave the following percentage composition : Na= 29.11%, S= 40.51% and O= 30.38%. Calculate the empirical formula of the salt. (At. Mass Na= 23, S=32)

An organic compound has the following percentage composition : C= 48%, H= 8% N= 28% and rest of oxygen. Calculate the empirical formula of the compound.

On analysis a substance was found to contain C = 54.54% H = 9.09% O = 36.36% . calculate the empirical formula.

An organic compound on analysis gave the following data : C = 57.82% , H = 3.6% and O = 38.58% . Find its empirical formula.

Calculate the percentage composition of C2H5OH.

Convert the following ratios to percentages 3:2

An organic compound on analysis gave the following percentage composition of C= 57.8, H= 3.6 and the rest is oxygen. Vapour density of the compound is 83. Find out the molecular formula of the compound.