The compound adrenaline is realised in the human body in times of stress . It was found by experiment to have the composition 56.8 % C,6.50 % H,28.4 % O and 8.28% N. What is the empirical formula of adrenaline ?

A substance on analysis gave the following percentage composition Na = 43.4% C = 11.3% O = 45.3% Calculate the empirical formula.

An organic compound has the following percentage composition : C= 48%, H= 8% N= 28% and rest of oxygen. Calculate the empirical formula of the compound.

An organic compound on analysis gave the following data : C = 57.82% , H = 3.6% and O = 38.58% . Find its empirical formula.

On analysis a substance was found to contain C = 54.54% H = 9.09% O = 36.36% . calculate the empirical formula.

Write the empirical formulae of the compounds with the following percentage composition : Zn = 47.8% Cl = 52.2%

An organic compound on analysis gave the following percentage composition of C= 57.8, H= 3.6 and the rest is oxygen. Vapour density of the compound is 83. Find out the molecular formula of the compound.

Bicyclohexane was found to undergo two parallel first order rearrangements. At 730 K, the first order rate constant for the formation of cyclohexene was measured as 1.26 xx 10-4 sec-1 , and for the formation of methyl cyclopentane the rate constant was 3.8 xx 10-5 sec–1 . What is the percentage distribution of therearrangement products?

A sample of paramagnetic salt contains 2.0 xx 10^24 atomic dipoles each of dipole moment 1.5 xx 10^-23 JT^-1 . The sample is placed under a homogeneous magnetic field of 0.64 T, and cooled to a temperature of 4.2 K. The degree of magnetic saturation achieved is equal to 15%. What is the total dipole moment of the sample for a magnetic field of 0.98 T and a temperature of 2.8 K? (Assume Curie’s law)

An experiment measures quantities a,b,c and d and x is calculated from formula x=(ab^(1//2))/(c^(3//2)d^(3)) . The percentage errors in a,b,c and d are 2% , 4% , 6% and 1% respectively. What is the percentage error in x ?