Assume the solubility of `PbCl_(2)` in water I `SmolL^(-1)` and its solubility product is `K_(sp)`. The relation between `K_(sp)` and S is represented as `S=root(3)((K_(sp))/x)`. The value of x is …….

Answer

`4`

Explanation

`PbCl_(2)hArrPb^(2+)+2Cl_(-)`
`(S)" "(S)" "(S)`
`K_(sp)=[Pb^(2+)][Cl]^(2)`
`=Sxx(2S)^(2)=4S^(3)`
`:.S=root(3)((K_(sp))/4)`
`:.` Value of `x=4`