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CH(3)-CH(2)-underset(CH(3))underset(|)(C...

`CH_(3)-CH_(2)-underset(CH_(3))underset(|)(CH)-underset(OH)underset(|)(CH)-CH_(3)overset(Na)to(A)`
`CH_(3)CH_(2)OHoverset(HBr)to(B)`
`(A)+(B)to(C)`
The product (C ) will be:

A

`CH_(3)-CH_(2)-underset(CH_(3))underset(|)(CH)-underset(O-CH_(2)-CH_(3))underset(|" ")(C" ")-CH_(3)`

B

`CH_(3)-CH_(3)`

C

`CH_(3)-CH_(2)-underset(CH_(3))underset(|)(CH)-CH=CH_(3)`

D

`CH_(3)-CH=underset(CH_(3))underset(|)C-CH-CH_(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
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