It is observed that air is a homogeneous mixture of 20% by volume `O_(2)(g)` and `80%` by volume `N_(2)`(g). With the help of given information estimate the volume of air which is required for complete combustion of 360 g `C_(5)H_(12)`(g) at 1 atm and 273K

Options

A. 896L%
B. 2240L%
C. 4480L
D. Data insufficient

Answer

C

Explanation

`C_(5)H_(12)(g)+8O_(2)(g)to5CO_(2)(g)`
`+6H_(2)O(1)`
moles `360/72`
=5
`n_(O_(2))=5xx8=40`
Let `n_("air")=x`
then `x xx20/100=40`
`x=200`
`V_("air")=200xx22.4`
`=4480L`