The rate of the 1st order reaction, `AtoB` is `5xx10^(-5)Mmin^(-1)`. When the concentration of A is 0.5 M, the rate cosntant is `1.0xx10^(-x)min^(-1)`. The value of x is

Answer

`4`

Explanation

Rate `=5xx10^(-5)M min^(-1)`
order =1
`[A]=0.5M`
The rate law is
Rate `=k[A]`
`:.5xx10^(-5)Mmin^(-1)=kxx0.5M`
`k=1.0xx10^(-4)min^(-1)`
Hence the value of `X` is 4.