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In a practical wheat stone bridge circui...

In a practical wheat stone bridge circuit as shown, when one more resistance of `100 Omega` is connected in parallel with unknown resistance 'x', then ratio `l_1//l_2` become '2'`l_1` is balance length , AB is a uniform wire. Then value of 'x' must be :

A

`50Omega`

B

`100Omega`

C

`200Omega`

D

`400 Omega`

Text Solution

Verified by Experts

The correct Answer is:
B

`:.` Wheat stone bridge is in balanced
condition
So `100/(l_(1))=(((100x)/(100+x)))/(l_(2))`
`:.(l_(1))/(l_(2))=2impliesx=100Omega`
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