The energy flux of the sunlight reaching the surface of the earth is `1.388xx10^(3) W m^(-2)`. How many photons (nearly) per square meter are incident on the earth per second? Assume that the photonsin the sunlight have an average wavelength of 550 nm.

Answer

`3.83`

Explanation

Power of sunlight per
`m^(2)=P=1.388xx10^(3)Wm^(-2)`
Average `lamda=550xx10^(-9)m`
Letn no. of photons per `m^(3)`incident on earth per second
`P=nE,E=(hc)/(lamda)`
`impliesn=3.84xx10^(21)` photons `m^(-2)s^(-1)`