A circuit `ABCD` is held perpendicular to the uinform magnetic field of `B = 5 xx 10^(-2)T` extending over the region `PQRS` and directed into the plane of the paper. The cicuit is moving out of the field at a uin form speed of `0.2 m s^(-1)` for `1.5 s`. During this time, the current in the `5 Omega` resistor is

Options

A. 0.6mA from B to C
B. 0.9 mA from B to C
C. 0.9 mA from C to B
D. 0.6 mA from C to B

Answer

A

Explanation

`I=(blv)/R`
`I=(5xx10^(-2)xx0.3xx0.2)/6A=0.6mA`.
Area and flux are deceasing. So current flows to increas the flux. Clearly, current shouldbe clockwise. So it flows from B to C through `5Omega`