The equation of a wave on a string of linear mass density `0.04 kg m^(-1)` is given by `y = 0.02 (m) sin [2pi((t)/(0.04(s))-(x)/(0.50(m)))]`. The tension in the string is :

Options

A. 4.0N
B. 12.5N
C. 0.25N
D. 6.25N

Answer

D

Explanation

Wave speed of transverse wave in a stretched string
`v=sqrt(T/(mu))`
`T=muv^(2)=mu(omega^(2))/(k^(2))=0.04(((2pi)/0.04)^(2))/(((2pi)/0.50)^(2))=6.25N`