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The efficiency of a Canot engine working...

The efficiency of a Canot engine working between `800K` and `500K` is

A

0.4

B

0.625

C

0.375

D

0.5

Text Solution

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The correct Answer is:
To find the efficiency of a Carnot engine working between two temperatures, we can use the formula for efficiency: \[ \text{Efficiency} = 1 - \frac{T_2}{T_1} \] Where: - \( T_1 \) is the higher temperature (in Kelvin) - \( T_2 \) is the lower temperature (in Kelvin) ### Step-by-Step Solution: 1. **Identify the temperatures**: - The higher temperature \( T_1 = 800 \, K \) - The lower temperature \( T_2 = 500 \, K \) 2. **Substitute the values into the efficiency formula**: \[ \text{Efficiency} = 1 - \frac{T_2}{T_1} = 1 - \frac{500}{800} \] 3. **Calculate the fraction**: \[ \frac{500}{800} = 0.625 \] 4. **Subtract from 1**: \[ \text{Efficiency} = 1 - 0.625 = 0.375 \] 5. **Convert to percentage (if needed)**: \[ \text{Efficiency} = 0.375 \times 100 = 37.5\% \] Thus, the efficiency of the Carnot engine working between 800 K and 500 K is **0.375** or **37.5%**.

To find the efficiency of a Carnot engine working between two temperatures, we can use the formula for efficiency: \[ \text{Efficiency} = 1 - \frac{T_2}{T_1} \] Where: - \( T_1 \) is the higher temperature (in Kelvin) ...
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Knowledge Check

  • Find the efficiency of a Carnot's engine working between 127^@ C and 27^@ C ?

    A
    0.35
    B
    25%,
    C
    0.5
    D
    60%.
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    A
    `T_(1) + 10` and `T_(2) + 10`
    B
    `T_(1) - 10` and `T_(2) - 10`
    C
    `2T_(1)` and `2T_(2)`
    D
    in all the above cases
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