What is the energy stored in the capacitor between terminals a and b of the network shown in the figure ? (Capacitance of each capacitance `C=1muF`)

Answer

`12.50`

Explanation

Redrawing network, we get a balanced Wheatston.s network.

Charge on capacitor between terminals a and b
`Q/2=(CV)/2`
Energy stored in that capacitor
`=1/2((Q/2)^(2))/C`
`=(Q^(2))/(8C)`
`=(CV^(2))/8`
`=(1xx10^(-6)xx10^(2)J)/8`
`=12.5muJ`