The ratio of amplitudes of two coherent waves in Young's double-slit experiemnt is `( A_(1))/(A_(2)) =(1)/( 3)`. What is the ratio of maximum and minimum intensities of fringes ?

Answer

`04.00`

Explanation

`(I_("max"))/(I_("min"))=((sqrt(I_(1))+sqrt(I_(2)))^(2))/((sqrt(I_(1))-sqrt(I_(2)))^(2))=((A_(1)+3A_(1))/(A_(1)-3A_(1)))^(2)`
`(I_("max"))/(I_("min"))=((A_(1)+3A_(1))/(A_(1)-3A_(1)))^(2)=(4/2)^(2)=4`