Power supplied to a particle of mass `2kg` varies with time as`P=3t^(2)/2` watt,where `t` is in seconds If velocity of particle at `t=0` is `v=0` the velocity of particle at `t=2` sec will be ?

Answer

`2`

Explanation

`K_(f)-K_(i)=intP.dt`
`1/2mv^(2)-0=int_(0)^(2)(3/2t^(2))dt` `1/2(2)v^(2)=3/2[(t^(3))/3]_(0)^(2)=4`
`v=2ms^(-1)`