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K("max") (in eV) = 3, and frequency of l...

`K_("max")` (in eV) = 3, and frequency of light (in Hz) `=1xx10^(15)` for a metal used as a cathode in a photoelectric experiment. The threshold frequency of light for the photoelectric emission from the metal is -

A

`1 xx 10^(14)Hz`

B

`1.5 xx 10^(14)Hz`

C

`2.1 xx 10^(14)Hz`

D

`2.7 xx 10^(14)Hz`

Text Solution

Verified by Experts

The correct Answer is:
D
Given, `K_(max)=3V` `h=4.125 xx 10^(-15)eVHz^(-1)` `hv=K_(max)+W`
`4.125xx10^(-15)xx10^(15)=3+W` or 4.125 = 3 + W or W=1.125 The threshold frequency
`nu_(0)=(W)/(h)` `nu_(0)=(1.125)/(4.125 xx 10^(-15))`
`nu_(0)=(1.125 xx 10^(-15))/(4.125)` `nu_(0)=2.72 xx 10^(14) Hz`
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