The figure shows the variation of force acting on a particle of mass 400 g executing simple harmonic motion. The
frequency of oscillation of the particle is

Options

A. `4 s^(-1)`
B. `(5//2 pi)s^(-1)`
C. `(1//8 pi)s^(-1)`
D. `(1//2 pi)s^(-1)`

Answer

B

Explanation

The slope of the curve is
`(F)/(x)=-(0.5)/(5)=-0.1(N)/(cm)=-10 N //m` But F =- `m omega^(2)x ` or `F//x=-m omega^(2)` so, `-m omega^(2)=-10 or omega^(2)=(10)/(m)`
`therefore omega^(2)=(10)/(4 xx 10^(-1)) implies omega =(10)/(2)=5` `therefore f=(omega)/(2 pi)=(5)/(2 pi)8^(-1)`