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The coefficient of friction between the ...

The coefficient of friction between the two blocks shown in the figure is `mu = 0.4` and between the lower block and the ground is zero. The blocks are given velocities of `2 ms^(-1)` and `8 ms^(-1)` respectively in the direction shown in the figure. In how much time (in seconds) the slipping between the blocks will stops ?

Text Solution

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The correct Answer is:
1
The common velocity of the blocks can be calculated as follows `3v=1xx2+2xx8 v=6 " ms"^(-1)`
The acceleration of the 1 kg block is
`a=mu g=4" ms"^(-2)`
`v=2+4t`
`implies t=1 s`
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